XCITYNIGERIA
WAEC 2018/2019 FURTHER MATHEMATICS QUESTIONS AND ANSWERS EXPO/RUNZ | 2018/2019 WAEC SSCE MAY/JUNE ELECTIVE MATHEMATICS OBJ AND THEORY QUESTIONS AND ANSWERS
FURTHER/ELECTIVE THEORY AND OBJ ANSWERS.
FURTHER MATHS OBJ:
1-10 BCADDDDDBB
11-20 CBACBBAABA
21-30 BCABBAABAB
31-40 CBADBDDCAB
MAY GOD BLESS YOU AS YOU ARE WRITING OUR ANSWERS
GOODLUCK
OBJ. L
THEORY ANSWERS.
*2018 WAEC MAY/JUNE FURTHER MATHS OBJ AND THEORY*
_Please Note the below symbols_
^ means raise to power
* means multiplication
/ means division
(1)
| x-3 -4 3 |
| 5 2 2 | = -24
| 2 -4 6-x |
(x-3)[2(6-x) +8]+4[5(6-x) -4]+3(-20-4) =-24
(x-3)[-2x+20]+4[-5x+26]+3(-24)= -24
-2x^2+26x-60-20x+104-72= -24
-2x^2+6x-4=0
X^2-3x+2=0
X^2-2x-x+2=0
X(x-2)-1(x-2)=0
(x-1)(x-2)=0
X-1=0 OR x-2=0
X=1 OR x=2
=-=-=-=-=-=-=-=-=-=-
(2)
Log 3x - 3logx³+ 2 = 0
Log 3x - 3log3³/log3x + 2 = 0
Log3x - 3/log3x + 2 = 0
P - 3/p + 2 = 0 where P = log3x
P² - 3 + 2p = 0
P² + 2p - 3 = 0
(p + 3) ( p - 1) = 0
P = -3 OR p = 1
But log3x = p
when p = -3
Log3x = -3
X = 3-³ = 1/27
And when P = 1
Log3x = 1
X = 3¹ = 3
And X = 1/27 OR 3
=-=-=-=-=-=-=-=
(3a)
U= x-2 ; hence X = u+2
Therefore :
X^3+5/(x-2)^4 = (u+2)^3+5/ (u+2-2)^4
=(u+2)^3+5/u^4
(3b)
(u+2)^3+5/u^4 = (u+2)^3/u^4 + 5/u^4
=-=-=-=-
(5)
TABULATE
cooking oil type|a|b|c|d|e|f|g|h
x|8|5|1|7|2|6|3|4
y|6|3|4|8|5|7|1|8
d|2|2|-3|-1|-3|-1|2|2
d²|4|4|9|1|9|1|4|4
£d² = 4+4+9+1+9+1+4+4 = 36
r = 1- 6£d²/n(n²-1)
= 1 - 6×36/8(8²-1)
= 1 - 216/504
= 1 - 0.43
= 0.57
=-=-=-=-=-
(5)
TABULATE
cooking oil type|a|b|c|d|e|f|g|h
x|8|5|1|7|2|6|3|4
y|6|3|4|8|5|7|1|8
d|2|2|-3|-1|-3|-1|2|2
d²|4|4|9|1|9|1|4|4
£d² = 4+4+9+1+9+1+4+4 = 36
r = 1- 6£d²/n(n²-1)
= 1 - 6×36/8(8²-1)
= 1 - 216/504
= 1 - 0.43
= 0.57
=-=-=-=-=-=-=-=-=-=-=-=
=-=-=-=-=-=-=-=-=-=-
(6a)
It follow that:
P(n) = 1/3 and p(k)¹ = 1 - 1/3 = 2/3
P(T) = 1/5 and P(T)¹ = 1- 1/5 = 4/5
Hence,
probability that only one if the them will be solve the questions will be:
= (1/3 × 4/5) + (1/5 × 2/3)
= 4/15 + 2/15
= 6/15
= 2/5
=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=
(7)
m = 3i - 2j ; n = 2i + 3j ; p = i + 6j
Therefore:
4(3i - 2j) +2(2i +3j) -3(-i + 6j)
12i - 8j + 4i + 6j + 3i - 18j
12i + 4i + 3i - 8j + 6j - 18j
19i = 20j
=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-
(
m1 = 20kg
u1 = 8ms-1
m2 = 30kg
u2 = 50ms-1
(a)
In same direction
m1u1 + m2u2 = (m1+m2)v
20 × 80 + 30 × 50 = (20+30)v
1600+1500 = 50v
3100/50 = 50/50
V = 62ms-1
(b)
In opposite direction
m1u1 - m2u2 = (m1 + u2)V
20×30 - 30×50 = (20+30)V
1600 - 1500 = 50V
100/50 = 50V/50
V = 2m/s
(15)
(a)
DRAW THE DIAGRAM
(b)
(2.2) + 80(0.6) = 300(1.2) + 100 (3)
2.2B + 48 = 360 + 300
2.B + 48 = 660
2.2B = 660 - 48
2.2B = 612
Reation at B = 278.18N
Taking moment about B
80(2.1) + 300(1) = 2.2A + 100 (0.
224 + 300 = 2.3A + 80
524 - 80 = 2.2A
A = 444/2.2
Reaction a+ A = 201.82N
(9)
Draw the pie chart diagram
radius is the same hence
(y - 2)² + (X - 3)² = (y + 4)² + (X - 5)² = (y + 1)² + (X + 2)²
Taking the first pair
Y² - 4y + 4 + x² - 6x + 9 = y² + 8y + 16 + x² - 10x + 25
- 6x - 4y + 13 = -10x+8y+41
4x - 12y = 28
X = 3y = 7--------(1)
Taking the second pair
Y² + 3y + 16+x² - 10x+25 = y²+ 2y + 1 + x²+ 4x + 4
-10x + 3y + 41 = 4x + 2y + 5
14x - 6y = 36
7x - 3y = 18---------(2)
Eqn 2 minus Eqn 1
6x = 11
X = 11/6
Put this into Eqn (1)
11/6 - 3y = 7
3y = 11/6 - 7
3y = 11 - 42/6
3y = -31/6
y = -31/18
(a) coordinates of centre is (11/6, -31/18)
(b) Radius r = √(y-2)²+(x-3)²
r = √-31/18 -2)² + 11/6 - 3)²
r= √13.85 + 1.36
r = 3.9
© (X - 11/6)² + (y + 31/18)² = 3.9²
(X - 11/16)² + (y + 31/18)² = 15.21
NO 15

NO4

NO5

NO6

NO7

No 8
8
MORE L
KEEP REFRESHING THIS PAGE FOR YOUR FREE ANSWERS TO COME. **
======GOODLUCK====
FOR MORE DETAILS AND PROCEDURE CONTACT US ON:
- 09033749554 - NIGERIA
- +2349033749554 - SIERRALEONE, GHANA'S, GAMBIA, LIBERIA.
Email: xcitynigeria@gmail.com
1st website : www.xcitynigeria.wapsite.me
2nd website : http://www.xcitynigeria.wordpress.com
3rd website : http://www.xcitynigeria.blogspot.com
GOODLUCK.
-
08149838594
xcitynigeria@gmail.com
